Kr. Sarkar Jayanta vs Howard Zhong

120. US Open 2019, 2019 · Result 1–0 · English Opening: King's English Variation, Four Knights Variation (A28).

Howard Zhong20350

Kr. Sarkar Jayanta15671

Notation · 129 moves

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Game details

White: Kr. Sarkar Jayanta (1567)
Black: Howard Zhong (2035)
Result: 1–0
Event: 120. US Open 2019
Year: 2019
Opening: English Opening: King's English Variation, Four Knights Variation (A28)

About this chess game

This chess game between Kr. Sarkar Jayanta (1567) and Howard Zhong (2035) was played at 120. US Open 2019 in 2019 and finished 1–0. The opening was the English Opening: King's English Variation, Four Knights Variation (A28). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.

Looking for more Kr. Sarkar Jayanta games or Howard Zhong games? This Kr. Sarkar Jayanta vs Howard Zhong encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: King's English Variation, Four Knights Variation.

Frequently asked questions

Who won Kr. Sarkar Jayanta vs Howard Zhong?

Kr. Sarkar Jayanta vs Howard Zhong (2019) finished 1–0, a win for Kr. Sarkar Jayanta.

What opening was played in Kr. Sarkar Jayanta vs Howard Zhong?

The game opened with the English Opening: King's English Variation, Four Knights Variation (ECO A28).

Can I replay this chess game move by move?

Yes. Use the interactive board on this page to step through every move of Kr. Sarkar Jayanta vs Howard Zhong, or open it on the CipherChess analysis board to review it with the Stockfish engine.