Brandon Jacobson vs Akshat Chandra
SPICE Cup Open 2019, 2019 · Result 0–1 · Catalan Opening: Closed, Zagoryansky Variation (E08).
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Game details
- White
- Brandon Jacobson (2452)
- Black
- Akshat Chandra (2513)
- Result
- 0–1
- Event
- SPICE Cup Open 2019
- Year
- 2019
- Opening
- Catalan Opening: Closed, Zagoryansky Variation (E08)
About this chess game
This chess game between Brandon Jacobson (2452) and Akshat Chandra (2513) was played at SPICE Cup Open 2019 in 2019 and finished 0–1. The opening was the Catalan Opening: Closed, Zagoryansky Variation (E08). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Brandon Jacobson games or Akshat Chandra games? This Brandon Jacobson vs Akshat Chandra encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Catalan Opening: Closed, Zagoryansky Variation.
Frequently asked questions
Who won Brandon Jacobson vs Akshat Chandra?
Brandon Jacobson vs Akshat Chandra (2019) finished 0–1, a win for Akshat Chandra.
What opening was played in Brandon Jacobson vs Akshat Chandra?
The game opened with the Catalan Opening: Closed, Zagoryansky Variation (ECO E08).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Brandon Jacobson vs Akshat Chandra, or open it on the CipherChess analysis board to review it with the Stockfish engine.