Ramon Hurtado de Mendoza vs Haakon Opsahl
Buenos Aires ol pr-A, 1939 · Result 0–1 · Queen's Indian Defense: Yates Variation (E16).
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Game details
- White
- Ramon Hurtado de Mendoza (1568)
- Black
- Haakon Opsahl
- Result
- 0–1
- Event
- Buenos Aires ol pr-A
- Year
- 1939
- Opening
- Queen's Indian Defense: Yates Variation (E16)
About this chess game
This chess game between Ramon Hurtado de Mendoza (1568) and Haakon Opsahl was played at Buenos Aires ol pr-A in 1939 and finished 0–1. The opening was the Queen's Indian Defense: Yates Variation (E16). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Ramon Hurtado de Mendoza games or Haakon Opsahl games? This Ramon Hurtado de Mendoza vs Haakon Opsahl encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Indian Defense: Yates Variation.
Frequently asked questions
Who won Ramon Hurtado de Mendoza vs Haakon Opsahl?
Ramon Hurtado de Mendoza vs Haakon Opsahl (1939) finished 0–1, a win for Haakon Opsahl.
What opening was played in Ramon Hurtado de Mendoza vs Haakon Opsahl?
The game opened with the Queen's Indian Defense: Yates Variation (ECO E16).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Ramon Hurtado de Mendoza vs Haakon Opsahl, or open it on the CipherChess analysis board to review it with the Stockfish engine.