Anthony Howarth vs Eduardo Teodoro
Canada, 1992 · Result 0–1 · Zukertort Opening (A05).
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Game details
- White
- Anthony Howarth (1850)
- Black
- Eduardo Teodoro (2215)
- Result
- 0–1
- Event
- Canada
- Year
- 1992
- Opening
- Zukertort Opening (A05)
About this chess game
This chess game between Anthony Howarth (1850) and Eduardo Teodoro (2215) was played at Canada in 1992 and finished 0–1. The opening was the Zukertort Opening (A05). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Anthony Howarth games or Eduardo Teodoro games? This Anthony Howarth vs Eduardo Teodoro encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Zukertort Opening.
Frequently asked questions
Who won Anthony Howarth vs Eduardo Teodoro?
Anthony Howarth vs Eduardo Teodoro (1992) finished 0–1, a win for Eduardo Teodoro.
What opening was played in Anthony Howarth vs Eduardo Teodoro?
The game opened with the Zukertort Opening (ECO A05).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Anthony Howarth vs Eduardo Teodoro, or open it on the CipherChess analysis board to review it with the Stockfish engine.