Adam Horvath vs Tunde Mitlasovszki
2004 · Result 1–0 · Four Knights Game: Spanish Variation (C48).
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Game details
- White
- Adam Horvath (1652)
- Black
- Tunde Mitlasovszki (1660)
- Result
- 1–0
- Year
- 2004
- Opening
- Four Knights Game: Spanish Variation (C48)
About this chess game
This chess game between Adam Horvath (1652) and Tunde Mitlasovszki (1660) was played in 2004 and finished 1–0. The opening was the Four Knights Game: Spanish Variation (C48). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Adam Horvath games or Tunde Mitlasovszki games? This Adam Horvath vs Tunde Mitlasovszki encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Four Knights Game: Spanish Variation.
Frequently asked questions
Who won Adam Horvath vs Tunde Mitlasovszki?
Adam Horvath vs Tunde Mitlasovszki (2004) finished 1–0, a win for Adam Horvath.
What opening was played in Adam Horvath vs Tunde Mitlasovszki?
The game opened with the Four Knights Game: Spanish Variation (ECO C48).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Adam Horvath vs Tunde Mitlasovszki, or open it on the CipherChess analysis board to review it with the Stockfish engine.