Roland Honhon vs Harry Pohla
Huy Open, 1992 · Result 0–1 · Dutch Defense: Leningrad Variation, Warsaw Variation (A88).
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Game details
- White
- Roland Honhon (2033)
- Black
- Harry Pohla (1576)
- Result
- 0–1
- Event
- Huy Open
- Year
- 1992
- Opening
- Dutch Defense: Leningrad Variation, Warsaw Variation (A88)
About this chess game
This chess game between Roland Honhon (2033) and Harry Pohla (1576) was played at Huy Open in 1992 and finished 0–1. The opening was the Dutch Defense: Leningrad Variation, Warsaw Variation (A88). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Roland Honhon games or Harry Pohla games? This Roland Honhon vs Harry Pohla encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Dutch Defense: Leningrad Variation, Warsaw Variation.
Frequently asked questions
Who won Roland Honhon vs Harry Pohla?
Roland Honhon vs Harry Pohla (1992) finished 0–1, a win for Harry Pohla.
What opening was played in Roland Honhon vs Harry Pohla?
The game opened with the Dutch Defense: Leningrad Variation, Warsaw Variation (ECO A88).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Roland Honhon vs Harry Pohla, or open it on the CipherChess analysis board to review it with the Stockfish engine.