Seth Homa vs Yusuf Mansurov
32. Chicago Open 2023, 2023 · Result ½–½ · English Opening: King's English Variation, Two Knights Variation (A22).
Turn this game into your next win
Replay Seth Homa vs Yusuf Mansurov with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Seth Homa (2213)
- Black
- Yusuf Mansurov (1731)
- Result
- ½–½
- Event
- 32. Chicago Open 2023
- Year
- 2023
- Opening
- English Opening: King's English Variation, Two Knights Variation (A22)
About this chess game
This chess game between Seth Homa (2213) and Yusuf Mansurov (1731) was played at 32. Chicago Open 2023 in 2023 and finished ½–½. The opening was the English Opening: King's English Variation, Two Knights Variation (A22). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Seth Homa games or Yusuf Mansurov games? This Seth Homa vs Yusuf Mansurov encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: King's English Variation, Two Knights Variation.
Frequently asked questions
Who won Seth Homa vs Yusuf Mansurov?
Seth Homa vs Yusuf Mansurov (2023) finished ½–½, and the game was drawn.
What opening was played in Seth Homa vs Yusuf Mansurov?
The game opened with the English Opening: King's English Variation, Two Knights Variation (ECO A22).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Seth Homa vs Yusuf Mansurov, or open it on the CipherChess analysis board to review it with the Stockfish engine.