Rudi Hoerstmann vs Andreas Winkelmann
Oberliga Nord W 9697, 1997 · Result 1–0 · Nimzo-Indian Defense: Normal Variation (E47).
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Game details
- White
- Rudi Hoerstmann (2255)
- Black
- Andreas Winkelmann (2195)
- Result
- 1–0
- Event
- Oberliga Nord W 9697
- Year
- 1997
- Opening
- Nimzo-Indian Defense: Normal Variation (E47)
About this chess game
This chess game between Rudi Hoerstmann (2255) and Andreas Winkelmann (2195) was played at Oberliga Nord W 9697 in 1997 and finished 1–0. The opening was the Nimzo-Indian Defense: Normal Variation (E47). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Rudi Hoerstmann games or Andreas Winkelmann games? This Rudi Hoerstmann vs Andreas Winkelmann encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Nimzo-Indian Defense: Normal Variation.
Frequently asked questions
Who won Rudi Hoerstmann vs Andreas Winkelmann?
Rudi Hoerstmann vs Andreas Winkelmann (1997) finished 1–0, a win for Rudi Hoerstmann.
What opening was played in Rudi Hoerstmann vs Andreas Winkelmann?
The game opened with the Nimzo-Indian Defense: Normal Variation (ECO E47).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Rudi Hoerstmann vs Andreas Winkelmann, or open it on the CipherChess analysis board to review it with the Stockfish engine.