Van Huynh Ho vs Boris Alterman
Manila, 1992 · Result 0–1 · Benko Gambit Accepted: Fully Accepted Variation (A58).
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Game details
- White
- Van Huynh Ho (2360)
- Black
- Boris Alterman (2515)
- Result
- 0–1
- Event
- Manila
- Year
- 1992
- Opening
- Benko Gambit Accepted: Fully Accepted Variation (A58)
About this chess game
This chess game between Van Huynh Ho (2360) and Boris Alterman (2515) was played at Manila in 1992 and finished 0–1. The opening was the Benko Gambit Accepted: Fully Accepted Variation (A58). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Van Huynh Ho games or Boris Alterman games? This Van Huynh Ho vs Boris Alterman encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Benko Gambit Accepted: Fully Accepted Variation.
Frequently asked questions
Who won Van Huynh Ho vs Boris Alterman?
Van Huynh Ho vs Boris Alterman (1992) finished 0–1, a win for Boris Alterman.
What opening was played in Van Huynh Ho vs Boris Alterman?
The game opened with the Benko Gambit Accepted: Fully Accepted Variation (ECO A58).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Van Huynh Ho vs Boris Alterman, or open it on the CipherChess analysis board to review it with the Stockfish engine.