Harald Herndl vs Bernhard Laube
Austria, 1991 · Result 0–1 · Queen's Indian Defense: Fianchetto Variation (E15).
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Game details
- White
- Harald Herndl (2295)
- Black
- Bernhard Laube (2230)
- Result
- 0–1
- Event
- Austria
- Year
- 1991
- Opening
- Queen's Indian Defense: Fianchetto Variation (E15)
About this chess game
This chess game between Harald Herndl (2295) and Bernhard Laube (2230) was played at Austria in 1991 and finished 0–1. The opening was the Queen's Indian Defense: Fianchetto Variation (E15). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Harald Herndl games or Bernhard Laube games? This Harald Herndl vs Bernhard Laube encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Indian Defense: Fianchetto Variation.
Frequently asked questions
Who won Harald Herndl vs Bernhard Laube?
Harald Herndl vs Bernhard Laube (1991) finished 0–1, a win for Bernhard Laube.
What opening was played in Harald Herndl vs Bernhard Laube?
The game opened with the Queen's Indian Defense: Fianchetto Variation (ECO E15).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Harald Herndl vs Bernhard Laube, or open it on the CipherChess analysis board to review it with the Stockfish engine.