Herbert Hennemann vs Roland Reuter
2006 · Result 0–1 · Queen's Pawn Game: Zukertort Variation (D02).
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Game details
- White
- Herbert Hennemann (1508)
- Black
- Roland Reuter (1978)
- Result
- 0–1
- Year
- 2006
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Herbert Hennemann (1508) and Roland Reuter (1978) was played in 2006 and finished 0–1. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Herbert Hennemann games or Roland Reuter games? This Herbert Hennemann vs Roland Reuter encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Herbert Hennemann vs Roland Reuter?
Herbert Hennemann vs Roland Reuter (2006) finished 0–1, a win for Roland Reuter.
What opening was played in Herbert Hennemann vs Roland Reuter?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Herbert Hennemann vs Roland Reuter, or open it on the CipherChess analysis board to review it with the Stockfish engine.