Wyatt Hendrix vs Hervé Guineret
WS/H/894, 2022 · Result 1–0 · Indian Defense: Budapest Defense (A52).
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Game details
- White
- Wyatt Hendrix (1826)
- Black
- Hervé Guineret (1990)
- Result
- 1–0
- Event
- WS/H/894
- Year
- 2022
- Opening
- Indian Defense: Budapest Defense (A52)
About this chess game
This chess game between Wyatt Hendrix (1826) and Hervé Guineret (1990) was played at WS/H/894 in 2022 and finished 1–0. The opening was the Indian Defense: Budapest Defense (A52). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Wyatt Hendrix games or Hervé Guineret games? This Wyatt Hendrix vs Hervé Guineret encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Budapest Defense.
Frequently asked questions
Who won Wyatt Hendrix vs Hervé Guineret?
Wyatt Hendrix vs Hervé Guineret (2022) finished 1–0, a win for Wyatt Hendrix.
What opening was played in Wyatt Hendrix vs Hervé Guineret?
The game opened with the Indian Defense: Budapest Defense (ECO A52).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Wyatt Hendrix vs Hervé Guineret, or open it on the CipherChess analysis board to review it with the Stockfish engine.