William R Hartston vs Julian Thomas Farrand
BCF Ch Brighton ENG, 1972 · Result 1–0 · English Opening: Symmetrical Variation, Four Knights Variation (A35).
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Game details
- White
- William R Hartston (2420)
- Black
- Julian Thomas Farrand (2272)
- Result
- 1–0
- Event
- BCF Ch Brighton ENG
- Year
- 1972
- Opening
- English Opening: Symmetrical Variation, Four Knights Variation (A35)
About this chess game
This chess game between William R Hartston (2420) and Julian Thomas Farrand (2272) was played at BCF Ch Brighton ENG in 1972 and finished 1–0. The opening was the English Opening: Symmetrical Variation, Four Knights Variation (A35). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more William R Hartston games or Julian Thomas Farrand games? This William R Hartston vs Julian Thomas Farrand encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation, Four Knights Variation.
Frequently asked questions
Who won William R Hartston vs Julian Thomas Farrand?
William R Hartston vs Julian Thomas Farrand (1972) finished 1–0, a win for William R Hartston.
What opening was played in William R Hartston vs Julian Thomas Farrand?
The game opened with the English Opening: Symmetrical Variation, Four Knights Variation (ECO A35).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of William R Hartston vs Julian Thomas Farrand, or open it on the CipherChess analysis board to review it with the Stockfish engine.