Willibald Hartmann vs Helmut Lindner
Wiesbaden Open, 1993 · Result 1–0 · Indian Defense: Budapest Defense (A51).
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Game details
- White
- Willibald Hartmann (1655)
- Black
- Helmut Lindner (1923)
- Result
- 1–0
- Event
- Wiesbaden Open
- Year
- 1993
- Opening
- Indian Defense: Budapest Defense (A51)
About this chess game
This chess game between Willibald Hartmann (1655) and Helmut Lindner (1923) was played at Wiesbaden Open in 1993 and finished 1–0. The opening was the Indian Defense: Budapest Defense (A51). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Willibald Hartmann games or Helmut Lindner games? This Willibald Hartmann vs Helmut Lindner encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Budapest Defense.
Frequently asked questions
Who won Willibald Hartmann vs Helmut Lindner?
Willibald Hartmann vs Helmut Lindner (1993) finished 1–0, a win for Willibald Hartmann.
What opening was played in Willibald Hartmann vs Helmut Lindner?
The game opened with the Indian Defense: Budapest Defense (ECO A51).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Willibald Hartmann vs Helmut Lindner, or open it on the CipherChess analysis board to review it with the Stockfish engine.