Florin Gheorghiu vs Adrian Buza
Rumania, 1969 · Result 1–0 · English Opening: Symmetrical Variation, Mecking Variation (A39).
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Game details
- White
- Florin Gheorghiu (2540)
- Black
- Adrian Buza
- Result
- 1–0
- Event
- Rumania
- Year
- 1969
- Opening
- English Opening: Symmetrical Variation, Mecking Variation (A39)
About this chess game
This chess game between Florin Gheorghiu (2540) and Adrian Buza was played at Rumania in 1969 and finished 1–0. The opening was the English Opening: Symmetrical Variation, Mecking Variation (A39). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Florin Gheorghiu games or Adrian Buza games? This Florin Gheorghiu vs Adrian Buza encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation, Mecking Variation.
Frequently asked questions
Who won Florin Gheorghiu vs Adrian Buza?
Florin Gheorghiu vs Adrian Buza (1969) finished 1–0, a win for Florin Gheorghiu.
What opening was played in Florin Gheorghiu vs Adrian Buza?
The game opened with the English Opening: Symmetrical Variation, Mecking Variation (ECO A39).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Florin Gheorghiu vs Adrian Buza, or open it on the CipherChess analysis board to review it with the Stockfish engine.