Patrick Frost vs Rohan Shan Tze Navaratnam
11. Penang Open 2019, 2019 · Result 0–1 · English Opening: Symmetrical Variation, Anti-Benoni Variation, Spielmann Defense (A32).
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Game details
- White
- Patrick Frost (1017)
- Black
- Rohan Shan Tze Navaratnam (2118)
- Result
- 0–1
- Event
- 11. Penang Open 2019
- Year
- 2019
- Opening
- English Opening: Symmetrical Variation, Anti-Benoni Variation, Spielmann Defense (A32)
About this chess game
This chess game between Patrick Frost (1017) and Rohan Shan Tze Navaratnam (2118) was played at 11. Penang Open 2019 in 2019 and finished 0–1. The opening was the English Opening: Symmetrical Variation, Anti-Benoni Variation, Spielmann Defense (A32). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Patrick Frost games or Rohan Shan Tze Navaratnam games? This Patrick Frost vs Rohan Shan Tze Navaratnam encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation, Anti-Benoni Variation, Spielmann Defense.
Frequently asked questions
Who won Patrick Frost vs Rohan Shan Tze Navaratnam?
Patrick Frost vs Rohan Shan Tze Navaratnam (2019) finished 0–1, a win for Rohan Shan Tze Navaratnam.
What opening was played in Patrick Frost vs Rohan Shan Tze Navaratnam?
The game opened with the English Opening: Symmetrical Variation, Anti-Benoni Variation, Spielmann Defense (ECO A32).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Patrick Frost vs Rohan Shan Tze Navaratnam, or open it on the CipherChess analysis board to review it with the Stockfish engine.