Janelle Mae Frayna vs Romayn Brandsma
22. HZ Open 2018, 2018 · Result 1–0 · Catalan Opening: Closed, Zagoryansky Variation (E08).
Turn this game into your next win
Replay Janelle Mae Frayna vs Romayn Brandsma with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Janelle Mae Frayna (2278)
- Black
- Romayn Brandsma (1706)
- Result
- 1–0
- Event
- 22. HZ Open 2018
- Year
- 2018
- Opening
- Catalan Opening: Closed, Zagoryansky Variation (E08)
About this chess game
This chess game between Janelle Mae Frayna (2278) and Romayn Brandsma (1706) was played at 22. HZ Open 2018 in 2018 and finished 1–0. The opening was the Catalan Opening: Closed, Zagoryansky Variation (E08). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Janelle Mae Frayna games or Romayn Brandsma games? This Janelle Mae Frayna vs Romayn Brandsma encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Catalan Opening: Closed, Zagoryansky Variation.
Frequently asked questions
Who won Janelle Mae Frayna vs Romayn Brandsma?
Janelle Mae Frayna vs Romayn Brandsma (2018) finished 1–0, a win for Janelle Mae Frayna.
What opening was played in Janelle Mae Frayna vs Romayn Brandsma?
The game opened with the Catalan Opening: Closed, Zagoryansky Variation (ECO E08).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Janelle Mae Frayna vs Romayn Brandsma, or open it on the CipherChess analysis board to review it with the Stockfish engine.