Heribert Franke vs Bela Perenyi
Budapest, 1988 · Result 1–0 · Indian Defense: Knights Variation (A46).
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Game details
- White
- Heribert Franke (2395)
- Black
- Bela Perenyi (2370)
- Result
- 1–0
- Event
- Budapest
- Year
- 1988
- Opening
- Indian Defense: Knights Variation (A46)
About this chess game
This chess game between Heribert Franke (2395) and Bela Perenyi (2370) was played at Budapest in 1988 and finished 1–0. The opening was the Indian Defense: Knights Variation (A46). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Heribert Franke games or Bela Perenyi games? This Heribert Franke vs Bela Perenyi encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Knights Variation.
Frequently asked questions
Who won Heribert Franke vs Bela Perenyi?
Heribert Franke vs Bela Perenyi (1988) finished 1–0, a win for Heribert Franke.
What opening was played in Heribert Franke vs Bela Perenyi?
The game opened with the Indian Defense: Knights Variation (ECO A46).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Heribert Franke vs Bela Perenyi, or open it on the CipherChess analysis board to review it with the Stockfish engine.