Chess Game
William J Foo vs Bogdan Lalic
19. Prague Open 2020, 2020 · Result 0–1 · Indian Defense: Knights Variation (A46).
Bogdan Lalic1
William J Foo0
Notation · 74 moves
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1. d4 Nf6 2. g3 c5 3. Nf3 cxd4 4. Nxd4 Nc6 5. Bg2 g6 6. e4 Nxd4 7. Qxd4 d6 8. h3 Bg7 9. Be3 O-O 10. Qd2 d5 11. exd5 Nxd5 12. Bd4 Nf4 13. Qxf4 Bxd4 14. c3 Bg7 15. Nd2 Be6 16. O-O Qb6 17. Nc4 Qb5 18. b3 Rac8 19. Qe3 b6 20. Rac1 Qa6 21. Rc2 Bxc4 22. bxc4 e6 23. Rd1 Qa4 24. Qd2 Rxc4 25. Rdc1 Bf6 26. Bf1 Rd8 27. Qe3 Rc5 28. c4 Bg5 29. f4 Be7 30. Rd2 Rcc8 31. Rxd8+ Rxd8 32. Kh1 Qxa2 33. Re1 Bc5 34. Qf3 Qf2 35. Qxf2 Bxf2 36. Re4 a5 37. Kg2 Bc5 0–1
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About this game
This chess game between William J Foo (2186) and Bogdan Lalic (2402) was played at 19. Prague Open 2020 in 2020 and finished 0–1. The opening was the Indian Defense: Knights Variation (A46). Step through every move on the interactive board above, or open it on the CipherChess board to analyse the game with the engine. You can also explore more games by William J Foo and Bogdan Lalic from the CipherChess mega database.