Carlos Federico Ferrero vs Jorge Llivi Ibanez
3. Floripa Open 2017, 2017 · Result 1–0 · Ruy Lopez: Steinitz Defense (C62).
Turn this game into your next win
Replay Carlos Federico Ferrero vs Jorge Llivi Ibanez with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Carlos Federico Ferrero (1930)
- Black
- Jorge Llivi Ibanez (1710)
- Result
- 1–0
- Event
- 3. Floripa Open 2017
- Year
- 2017
- Opening
- Ruy Lopez: Steinitz Defense (C62)
About this chess game
This chess game between Carlos Federico Ferrero (1930) and Jorge Llivi Ibanez (1710) was played at 3. Floripa Open 2017 in 2017 and finished 1–0. The opening was the Ruy Lopez: Steinitz Defense (C62). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Carlos Federico Ferrero games or Jorge Llivi Ibanez games? This Carlos Federico Ferrero vs Jorge Llivi Ibanez encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Ruy Lopez: Steinitz Defense.
Frequently asked questions
Who won Carlos Federico Ferrero vs Jorge Llivi Ibanez?
Carlos Federico Ferrero vs Jorge Llivi Ibanez (2017) finished 1–0, a win for Carlos Federico Ferrero.
What opening was played in Carlos Federico Ferrero vs Jorge Llivi Ibanez?
The game opened with the Ruy Lopez: Steinitz Defense (ECO C62).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Carlos Federico Ferrero vs Jorge Llivi Ibanez, or open it on the CipherChess analysis board to review it with the Stockfish engine.