Roland Feng vs Amith Vanmane
2010 · Result 1–0 · King's Indian Defense: Orthodox Variation, Aronin-Taimanov Defense (E97).
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Game details
- White
- Roland Feng (1992)
- Black
- Amith Vanmane (1643)
- Result
- 1–0
- Year
- 2010
- Opening
- King's Indian Defense: Orthodox Variation, Aronin-Taimanov Defense (E97)
About this chess game
This chess game between Roland Feng (1992) and Amith Vanmane (1643) was played in 2010 and finished 1–0. The opening was the King's Indian Defense: Orthodox Variation, Aronin-Taimanov Defense (E97). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Roland Feng games or Amith Vanmane games? This Roland Feng vs Amith Vanmane encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the King's Indian Defense: Orthodox Variation, Aronin-Taimanov Defense.
Frequently asked questions
Who won Roland Feng vs Amith Vanmane?
Roland Feng vs Amith Vanmane (2010) finished 1–0, a win for Roland Feng.
What opening was played in Roland Feng vs Amith Vanmane?
The game opened with the King's Indian Defense: Orthodox Variation, Aronin-Taimanov Defense (ECO E97).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Roland Feng vs Amith Vanmane, or open it on the CipherChess analysis board to review it with the Stockfish engine.