Alexander A. Evdokimov vs Saptarshi Roy Chowdhury
14. Dubai Open, 2012 · Result 1–0 · Old Indian Defense: Normal Variation (A55).
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Game details
- White
- Alexander A. Evdokimov (2544)
- Black
- Saptarshi Roy Chowdhury (2391)
- Result
- 1–0
- Event
- 14. Dubai Open
- Year
- 2012
- Opening
- Old Indian Defense: Normal Variation (A55)
About this chess game
This chess game between Alexander A. Evdokimov (2544) and Saptarshi Roy Chowdhury (2391) was played at 14. Dubai Open in 2012 and finished 1–0. The opening was the Old Indian Defense: Normal Variation (A55). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alexander A. Evdokimov games or Saptarshi Roy Chowdhury games? This Alexander A. Evdokimov vs Saptarshi Roy Chowdhury encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Old Indian Defense: Normal Variation.
Frequently asked questions
Who won Alexander A. Evdokimov vs Saptarshi Roy Chowdhury?
Alexander A. Evdokimov vs Saptarshi Roy Chowdhury (2012) finished 1–0, a win for Alexander A. Evdokimov.
What opening was played in Alexander A. Evdokimov vs Saptarshi Roy Chowdhury?
The game opened with the Old Indian Defense: Normal Variation (ECO A55).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alexander A. Evdokimov vs Saptarshi Roy Chowdhury, or open it on the CipherChess analysis board to review it with the Stockfish engine.