Horst Dunkel vs Hubert Beutel
Corr BdF, 1989 · Result 1–0 · Queen's Indian Defense: Yates Variation (E16).
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Game details
- White
- Horst Dunkel (1993)
- Black
- Hubert Beutel (2270)
- Result
- 1–0
- Event
- Corr BdF
- Year
- 1989
- Opening
- Queen's Indian Defense: Yates Variation (E16)
About this chess game
This chess game between Horst Dunkel (1993) and Hubert Beutel (2270) was played at Corr BdF in 1989 and finished 1–0. The opening was the Queen's Indian Defense: Yates Variation (E16). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Horst Dunkel games or Hubert Beutel games? This Horst Dunkel vs Hubert Beutel encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Indian Defense: Yates Variation.
Frequently asked questions
Who won Horst Dunkel vs Hubert Beutel?
Horst Dunkel vs Hubert Beutel (1989) finished 1–0, a win for Horst Dunkel.
What opening was played in Horst Dunkel vs Hubert Beutel?
The game opened with the Queen's Indian Defense: Yates Variation (ECO E16).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Horst Dunkel vs Hubert Beutel, or open it on the CipherChess analysis board to review it with the Stockfish engine.