Pavel Dumakov vs Leonid Zlachevskiy
2017 · Result 1–0 · English Opening: King's English Variation, Two Knights Variation (A22).
Turn this game into your next win
Replay Pavel Dumakov vs Leonid Zlachevskiy with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Pavel Dumakov (1878)
- Black
- Leonid Zlachevskiy (2066)
- Result
- 1–0
- Year
- 2017
- Opening
- English Opening: King's English Variation, Two Knights Variation (A22)
About this chess game
This chess game between Pavel Dumakov (1878) and Leonid Zlachevskiy (2066) was played in 2017 and finished 1–0. The opening was the English Opening: King's English Variation, Two Knights Variation (A22). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Pavel Dumakov games or Leonid Zlachevskiy games? This Pavel Dumakov vs Leonid Zlachevskiy encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: King's English Variation, Two Knights Variation.
Frequently asked questions
Who won Pavel Dumakov vs Leonid Zlachevskiy?
Pavel Dumakov vs Leonid Zlachevskiy (2017) finished 1–0, a win for Pavel Dumakov.
What opening was played in Pavel Dumakov vs Leonid Zlachevskiy?
The game opened with the English Opening: King's English Variation, Two Knights Variation (ECO A22).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Pavel Dumakov vs Leonid Zlachevskiy, or open it on the CipherChess analysis board to review it with the Stockfish engine.