Herve Dubois vs Quentin Bertrand
2007 · Result 1–0 · Dutch Defense: Leningrad Variation (A87).
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Game details
- White
- Herve Dubois (1953)
- Black
- Quentin Bertrand (1780)
- Result
- 1–0
- Year
- 2007
- Opening
- Dutch Defense: Leningrad Variation (A87)
About this chess game
This chess game between Herve Dubois (1953) and Quentin Bertrand (1780) was played in 2007 and finished 1–0. The opening was the Dutch Defense: Leningrad Variation (A87). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Herve Dubois games or Quentin Bertrand games? This Herve Dubois vs Quentin Bertrand encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Dutch Defense: Leningrad Variation.
Frequently asked questions
Who won Herve Dubois vs Quentin Bertrand?
Herve Dubois vs Quentin Bertrand (2007) finished 1–0, a win for Herve Dubois.
What opening was played in Herve Dubois vs Quentin Bertrand?
The game opened with the Dutch Defense: Leningrad Variation (ECO A87).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Herve Dubois vs Quentin Bertrand, or open it on the CipherChess analysis board to review it with the Stockfish engine.