Ernesto Dillenschneider vs Alexandre Zienkiewicz
2020 · Result 1–0 · Old Indian Defense: Normal Variation (A55).
Turn this game into your next win
Replay Ernesto Dillenschneider vs Alexandre Zienkiewicz with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Ernesto Dillenschneider (2001)
- Black
- Alexandre Zienkiewicz (2049)
- Result
- 1–0
- Year
- 2020
- Opening
- Old Indian Defense: Normal Variation (A55)
About this chess game
This chess game between Ernesto Dillenschneider (2001) and Alexandre Zienkiewicz (2049) was played in 2020 and finished 1–0. The opening was the Old Indian Defense: Normal Variation (A55). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Ernesto Dillenschneider games or Alexandre Zienkiewicz games? This Ernesto Dillenschneider vs Alexandre Zienkiewicz encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Old Indian Defense: Normal Variation.
Frequently asked questions
Who won Ernesto Dillenschneider vs Alexandre Zienkiewicz?
Ernesto Dillenschneider vs Alexandre Zienkiewicz (2020) finished 1–0, a win for Ernesto Dillenschneider.
What opening was played in Ernesto Dillenschneider vs Alexandre Zienkiewicz?
The game opened with the Old Indian Defense: Normal Variation (ECO A55).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Ernesto Dillenschneider vs Alexandre Zienkiewicz, or open it on the CipherChess analysis board to review it with the Stockfish engine.