Alessandro Di Sante vs Matteo Cristicchia
XIII Weekend U16, 2010 · Result 0–1 · Queen's Pawn Game: Zukertort Variation (D02).
Turn this game into your next win
Replay Alessandro Di Sante vs Matteo Cristicchia with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Alessandro Di Sante (1401)
- Black
- Matteo Cristicchia (1607)
- Result
- 0–1
- Event
- XIII Weekend U16
- Year
- 2010
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Alessandro Di Sante (1401) and Matteo Cristicchia (1607) was played at XIII Weekend U16 in 2010 and finished 0–1. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alessandro Di Sante games or Matteo Cristicchia games? This Alessandro Di Sante vs Matteo Cristicchia encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Alessandro Di Sante vs Matteo Cristicchia?
Alessandro Di Sante vs Matteo Cristicchia (2010) finished 0–1, a win for Matteo Cristicchia.
What opening was played in Alessandro Di Sante vs Matteo Cristicchia?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alessandro Di Sante vs Matteo Cristicchia, or open it on the CipherChess analysis board to review it with the Stockfish engine.