Joao Arthur Solak De Souza vs Henrik Stepanyan
FIDE World Bl Team Pool C, 2025 · Result 1–0 · King's Knight Opening (C40).
Turn this game into your next win
Replay Joao Arthur Solak De Souza vs Henrik Stepanyan with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Joao Arthur Solak De Souza (1177)
- Black
- Henrik Stepanyan (2200)
- Result
- 1–0
- Event
- FIDE World Bl Team Pool C
- Year
- 2025
- Opening
- King's Knight Opening (C40)
About this chess game
This chess game between Joao Arthur Solak De Souza (1177) and Henrik Stepanyan (2200) was played at FIDE World Bl Team Pool C in 2025 and finished 1–0. The opening was the King's Knight Opening (C40). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Joao Arthur Solak De Souza games or Henrik Stepanyan games? This Joao Arthur Solak De Souza vs Henrik Stepanyan encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the King's Knight Opening.
Frequently asked questions
Who won Joao Arthur Solak De Souza vs Henrik Stepanyan?
Joao Arthur Solak De Souza vs Henrik Stepanyan (2025) finished 1–0, a win for Joao Arthur Solak De Souza.
What opening was played in Joao Arthur Solak De Souza vs Henrik Stepanyan?
The game opened with the King's Knight Opening (ECO C40).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Joao Arthur Solak De Souza vs Henrik Stepanyan, or open it on the CipherChess analysis board to review it with the Stockfish engine.