Leandro Da Silva Espinola vs Marcos Tadeu Barbosa Moreira
2020 · Result 0–1 · Zukertort Opening (A06).
Turn this game into your next win
Replay Leandro Da Silva Espinola vs Marcos Tadeu Barbosa Moreira with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Leandro Da Silva Espinola (1850)
- Black
- Marcos Tadeu Barbosa Moreira (1502)
- Result
- 0–1
- Year
- 2020
- Opening
- Zukertort Opening (A06)
About this chess game
This chess game between Leandro Da Silva Espinola (1850) and Marcos Tadeu Barbosa Moreira (1502) was played in 2020 and finished 0–1. The opening was the Zukertort Opening (A06). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Leandro Da Silva Espinola games or Marcos Tadeu Barbosa Moreira games? This Leandro Da Silva Espinola vs Marcos Tadeu Barbosa Moreira encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Zukertort Opening.
Frequently asked questions
Who won Leandro Da Silva Espinola vs Marcos Tadeu Barbosa Moreira?
Leandro Da Silva Espinola vs Marcos Tadeu Barbosa Moreira (2020) finished 0–1, a win for Marcos Tadeu Barbosa Moreira.
What opening was played in Leandro Da Silva Espinola vs Marcos Tadeu Barbosa Moreira?
The game opened with the Zukertort Opening (ECO A06).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Leandro Da Silva Espinola vs Marcos Tadeu Barbosa Moreira, or open it on the CipherChess analysis board to review it with the Stockfish engine.