David Cornell vs Arkadiusz Polaszek
Corr, 1999 · Result 0–1 · Queen's Pawn Game: Zukertort Variation (D02).
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Game details
- White
- David Cornell (1707)
- Black
- Arkadiusz Polaszek (1898)
- Result
- 0–1
- Event
- Corr
- Year
- 1999
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between David Cornell (1707) and Arkadiusz Polaszek (1898) was played at Corr in 1999 and finished 0–1. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more David Cornell games or Arkadiusz Polaszek games? This David Cornell vs Arkadiusz Polaszek encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won David Cornell vs Arkadiusz Polaszek?
David Cornell vs Arkadiusz Polaszek (1999) finished 0–1, a win for Arkadiusz Polaszek.
What opening was played in David Cornell vs Arkadiusz Polaszek?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of David Cornell vs Arkadiusz Polaszek, or open it on the CipherChess analysis board to review it with the Stockfish engine.