Paul S Cooksey vs Simon T Ansell
4NCL 2012-13, 2013 · Result 1–0 · King's Indian Defense: Fianchetto Variation, Long Variation (E68).
Turn this game into your next win
Replay Paul S Cooksey vs Simon T Ansell with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Paul S Cooksey (2279)
- Black
- Simon T Ansell (2391)
- Result
- 1–0
- Event
- 4NCL 2012-13
- Year
- 2013
- Opening
- King's Indian Defense: Fianchetto Variation, Long Variation (E68)
About this chess game
This chess game between Paul S Cooksey (2279) and Simon T Ansell (2391) was played at 4NCL 2012-13 in 2013 and finished 1–0. The opening was the King's Indian Defense: Fianchetto Variation, Long Variation (E68). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Paul S Cooksey games or Simon T Ansell games? This Paul S Cooksey vs Simon T Ansell encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the King's Indian Defense: Fianchetto Variation, Long Variation.
Frequently asked questions
Who won Paul S Cooksey vs Simon T Ansell?
Paul S Cooksey vs Simon T Ansell (2013) finished 1–0, a win for Paul S Cooksey.
What opening was played in Paul S Cooksey vs Simon T Ansell?
The game opened with the King's Indian Defense: Fianchetto Variation, Long Variation (ECO E68).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Paul S Cooksey vs Simon T Ansell, or open it on the CipherChess analysis board to review it with the Stockfish engine.