Teddy Coleman vs Joshua Friedel
North American Open, 2010 · Result 0–1 · Nimzo-Indian Defense: Normal Variation, Ragozin Variation (E51).
Turn this game into your next win
Replay Teddy Coleman vs Joshua Friedel with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Teddy Coleman (2282)
- Black
- Joshua Friedel (2505)
- Result
- 0–1
- Event
- North American Open
- Year
- 2010
- Opening
- Nimzo-Indian Defense: Normal Variation, Ragozin Variation (E51)
About this chess game
This chess game between Teddy Coleman (2282) and Joshua Friedel (2505) was played at North American Open in 2010 and finished 0–1. The opening was the Nimzo-Indian Defense: Normal Variation, Ragozin Variation (E51). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Teddy Coleman games or Joshua Friedel games? This Teddy Coleman vs Joshua Friedel encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Nimzo-Indian Defense: Normal Variation, Ragozin Variation.
Frequently asked questions
Who won Teddy Coleman vs Joshua Friedel?
Teddy Coleman vs Joshua Friedel (2010) finished 0–1, a win for Joshua Friedel.
What opening was played in Teddy Coleman vs Joshua Friedel?
The game opened with the Nimzo-Indian Defense: Normal Variation, Ragozin Variation (ECO E51).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Teddy Coleman vs Joshua Friedel, or open it on the CipherChess analysis board to review it with the Stockfish engine.