Brandon G I Clarke vs Zong-Yuan Zhao
Gold Coast Open 2018, 2018 · Result ½–½ · Sicilian Defense: Taimanov Variation, Bastrikov Variation, English Attack (B48).
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Game details
- White
- Brandon G I Clarke (2411)
- Black
- Zong-Yuan Zhao (2533)
- Result
- ½–½
- Event
- Gold Coast Open 2018
- Year
- 2018
- Opening
- Sicilian Defense: Taimanov Variation, Bastrikov Variation, English Attack (B48)
About this chess game
This chess game between Brandon G I Clarke (2411) and Zong-Yuan Zhao (2533) was played at Gold Coast Open 2018 in 2018 and finished ½–½. The opening was the Sicilian Defense: Taimanov Variation, Bastrikov Variation, English Attack (B48). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Brandon G I Clarke games or Zong-Yuan Zhao games? This Brandon G I Clarke vs Zong-Yuan Zhao encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Taimanov Variation, Bastrikov Variation, English Attack.
Frequently asked questions
Who won Brandon G I Clarke vs Zong-Yuan Zhao?
Brandon G I Clarke vs Zong-Yuan Zhao (2018) finished ½–½, and the game was drawn.
What opening was played in Brandon G I Clarke vs Zong-Yuan Zhao?
The game opened with the Sicilian Defense: Taimanov Variation, Bastrikov Variation, English Attack (ECO B48).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Brandon G I Clarke vs Zong-Yuan Zhao, or open it on the CipherChess analysis board to review it with the Stockfish engine.