Alexander RZ Chang vs Arkadiusz Luksza
Montreal Open 2017, 2017 · Result 0–1 · French Defense: Exchange Variation (C01).
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Game details
- White
- Alexander RZ Chang (1373)
- Black
- Arkadiusz Luksza (2108)
- Result
- 0–1
- Event
- Montreal Open 2017
- Year
- 2017
- Opening
- French Defense: Exchange Variation (C01)
About this chess game
This chess game between Alexander RZ Chang (1373) and Arkadiusz Luksza (2108) was played at Montreal Open 2017 in 2017 and finished 0–1. The opening was the French Defense: Exchange Variation (C01). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alexander RZ Chang games or Arkadiusz Luksza games? This Alexander RZ Chang vs Arkadiusz Luksza encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the French Defense: Exchange Variation.
Frequently asked questions
Who won Alexander RZ Chang vs Arkadiusz Luksza?
Alexander RZ Chang vs Arkadiusz Luksza (2017) finished 0–1, a win for Arkadiusz Luksza.
What opening was played in Alexander RZ Chang vs Arkadiusz Luksza?
The game opened with the French Defense: Exchange Variation (ECO C01).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alexander RZ Chang vs Arkadiusz Luksza, or open it on the CipherChess analysis board to review it with the Stockfish engine.