Rodolfo Cantero vs Carlos Fermin Medina
2018 · Result 1–0 · Sicilian Defense: Najdorf Variation, Opocensky Variation (B92).
Turn this game into your next win
Replay Rodolfo Cantero vs Carlos Fermin Medina with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Rodolfo Cantero (2067)
- Black
- Carlos Fermin Medina (1529)
- Result
- 1–0
- Year
- 2018
- Opening
- Sicilian Defense: Najdorf Variation, Opocensky Variation (B92)
About this chess game
This chess game between Rodolfo Cantero (2067) and Carlos Fermin Medina (1529) was played in 2018 and finished 1–0. The opening was the Sicilian Defense: Najdorf Variation, Opocensky Variation (B92). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Rodolfo Cantero games or Carlos Fermin Medina games? This Rodolfo Cantero vs Carlos Fermin Medina encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Najdorf Variation, Opocensky Variation.
Frequently asked questions
Who won Rodolfo Cantero vs Carlos Fermin Medina?
Rodolfo Cantero vs Carlos Fermin Medina (2018) finished 1–0, a win for Rodolfo Cantero.
What opening was played in Rodolfo Cantero vs Carlos Fermin Medina?
The game opened with the Sicilian Defense: Najdorf Variation, Opocensky Variation (ECO B92).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Rodolfo Cantero vs Carlos Fermin Medina, or open it on the CipherChess analysis board to review it with the Stockfish engine.