Romain Candy vs Alexandre Feryn
2009 · Result 1–0 · Sicilian Defense: Taimanov Variation, Bastrikov Variation, English Attack (B48).
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Game details
- White
- Romain Candy (2118)
- Black
- Alexandre Feryn (2044)
- Result
- 1–0
- Year
- 2009
- Opening
- Sicilian Defense: Taimanov Variation, Bastrikov Variation, English Attack (B48)
About this chess game
This chess game between Romain Candy (2118) and Alexandre Feryn (2044) was played in 2009 and finished 1–0. The opening was the Sicilian Defense: Taimanov Variation, Bastrikov Variation, English Attack (B48). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Romain Candy games or Alexandre Feryn games? This Romain Candy vs Alexandre Feryn encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Taimanov Variation, Bastrikov Variation, English Attack.
Frequently asked questions
Who won Romain Candy vs Alexandre Feryn?
Romain Candy vs Alexandre Feryn (2009) finished 1–0, a win for Romain Candy.
What opening was played in Romain Candy vs Alexandre Feryn?
The game opened with the Sicilian Defense: Taimanov Variation, Bastrikov Variation, English Attack (ECO B48).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Romain Candy vs Alexandre Feryn, or open it on the CipherChess analysis board to review it with the Stockfish engine.