Vladimir Burmakin vs Mitra Santu
2. Goa Open 2019, 2019 · Result 1–0 · Zukertort Opening (A05).
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Game details
- White
- Vladimir Burmakin (2526)
- Black
- Mitra Santu (1327)
- Result
- 1–0
- Event
- 2. Goa Open 2019
- Year
- 2019
- Opening
- Zukertort Opening (A05)
About this chess game
This chess game between Vladimir Burmakin (2526) and Mitra Santu (1327) was played at 2. Goa Open 2019 in 2019 and finished 1–0. The opening was the Zukertort Opening (A05). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Vladimir Burmakin games or Mitra Santu games? This Vladimir Burmakin vs Mitra Santu encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Zukertort Opening.
Frequently asked questions
Who won Vladimir Burmakin vs Mitra Santu?
Vladimir Burmakin vs Mitra Santu (2019) finished 1–0, a win for Vladimir Burmakin.
What opening was played in Vladimir Burmakin vs Mitra Santu?
The game opened with the Zukertort Opening (ECO A05).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Vladimir Burmakin vs Mitra Santu, or open it on the CipherChess analysis board to review it with the Stockfish engine.