Harold Brown vs Alex Kuznecov
Fraser Valley Open, 1985 · Result 0–1 · Grünfeld Defense: Three Knights Variation, Hungarian Variation (D93).
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Game details
- White
- Harold Brown
- Black
- Alex Kuznecov (2350)
- Result
- 0–1
- Event
- Fraser Valley Open
- Year
- 1985
- Opening
- Grünfeld Defense: Three Knights Variation, Hungarian Variation (D93)
About this chess game
This chess game between Harold Brown and Alex Kuznecov (2350) was played at Fraser Valley Open in 1985 and finished 0–1. The opening was the Grünfeld Defense: Three Knights Variation, Hungarian Variation (D93). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Harold Brown games or Alex Kuznecov games? This Harold Brown vs Alex Kuznecov encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Grünfeld Defense: Three Knights Variation, Hungarian Variation.
Frequently asked questions
Who won Harold Brown vs Alex Kuznecov?
Harold Brown vs Alex Kuznecov (1985) finished 0–1, a win for Alex Kuznecov.
What opening was played in Harold Brown vs Alex Kuznecov?
The game opened with the Grünfeld Defense: Three Knights Variation, Hungarian Variation (ECO D93).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Harold Brown vs Alex Kuznecov, or open it on the CipherChess analysis board to review it with the Stockfish engine.