Tim Broome vs Bernard Angles d'Auriac
Moskou olm, 1994 · Result 1–0 · Bird Opening: Dutch Variation (A03).
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Game details
- White
- Tim Broome (2025)
- Black
- Bernard Angles d'Auriac (1958)
- Result
- 1–0
- Event
- Moskou olm
- Year
- 1994
- Opening
- Bird Opening: Dutch Variation (A03)
About this chess game
This chess game between Tim Broome (2025) and Bernard Angles d'Auriac (1958) was played at Moskou olm in 1994 and finished 1–0. The opening was the Bird Opening: Dutch Variation (A03). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Tim Broome games or Bernard Angles d'Auriac games? This Tim Broome vs Bernard Angles d'Auriac encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Bird Opening: Dutch Variation.
Frequently asked questions
Who won Tim Broome vs Bernard Angles d'Auriac?
Tim Broome vs Bernard Angles d'Auriac (1994) finished 1–0, a win for Tim Broome.
What opening was played in Tim Broome vs Bernard Angles d'Auriac?
The game opened with the Bird Opening: Dutch Variation (ECO A03).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Tim Broome vs Bernard Angles d'Auriac, or open it on the CipherChess analysis board to review it with the Stockfish engine.