Alexander Brodie vs Howard Staunton
London, 1851 · Result 0–1 · English Opening: Symmetrical Variation (A30).
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Game details
- White
- Alexander Brodie (1499)
- Black
- Howard Staunton
- Result
- 0–1
- Event
- London
- Year
- 1851
- Opening
- English Opening: Symmetrical Variation (A30)
About this chess game
This chess game between Alexander Brodie (1499) and Howard Staunton was played at London in 1851 and finished 0–1. The opening was the English Opening: Symmetrical Variation (A30). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alexander Brodie games or Howard Staunton games? This Alexander Brodie vs Howard Staunton encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation.
Frequently asked questions
Who won Alexander Brodie vs Howard Staunton?
Alexander Brodie vs Howard Staunton (1851) finished 0–1, a win for Howard Staunton.
What opening was played in Alexander Brodie vs Howard Staunton?
The game opened with the English Opening: Symmetrical Variation (ECO A30).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alexander Brodie vs Howard Staunton, or open it on the CipherChess analysis board to review it with the Stockfish engine.