Thierry Brionne vs Roland Weill
Frankrijk tt, 1989 · Result 0–1 · Modern Defense: Averbakh Variation, Pseudo-Sämisch (A42).
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Game details
- White
- Thierry Brionne (2205)
- Black
- Roland Weill (2225)
- Result
- 0–1
- Event
- Frankrijk tt
- Year
- 1989
- Opening
- Modern Defense: Averbakh Variation, Pseudo-Sämisch (A42)
About this chess game
This chess game between Thierry Brionne (2205) and Roland Weill (2225) was played at Frankrijk tt in 1989 and finished 0–1. The opening was the Modern Defense: Averbakh Variation, Pseudo-Sämisch (A42). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Thierry Brionne games or Roland Weill games? This Thierry Brionne vs Roland Weill encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Modern Defense: Averbakh Variation, Pseudo-Sämisch.
Frequently asked questions
Who won Thierry Brionne vs Roland Weill?
Thierry Brionne vs Roland Weill (1989) finished 0–1, a win for Roland Weill.
What opening was played in Thierry Brionne vs Roland Weill?
The game opened with the Modern Defense: Averbakh Variation, Pseudo-Sämisch (ECO A42).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Thierry Brionne vs Roland Weill, or open it on the CipherChess analysis board to review it with the Stockfish engine.