Lo Alexander Bravo Jaramillo vs Eric Mendoza Sosaya
2010 · Result 1–0 · Ruy Lopez: Exchange Variation (C68).
Turn this game into your next win
Replay Lo Alexander Bravo Jaramillo vs Eric Mendoza Sosaya with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Lo Alexander Bravo Jaramillo (1763)
- Black
- Eric Mendoza Sosaya (1659)
- Result
- 1–0
- Year
- 2010
- Opening
- Ruy Lopez: Exchange Variation (C68)
About this chess game
This chess game between Lo Alexander Bravo Jaramillo (1763) and Eric Mendoza Sosaya (1659) was played in 2010 and finished 1–0. The opening was the Ruy Lopez: Exchange Variation (C68). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Lo Alexander Bravo Jaramillo games or Eric Mendoza Sosaya games? This Lo Alexander Bravo Jaramillo vs Eric Mendoza Sosaya encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Ruy Lopez: Exchange Variation.
Frequently asked questions
Who won Lo Alexander Bravo Jaramillo vs Eric Mendoza Sosaya?
Lo Alexander Bravo Jaramillo vs Eric Mendoza Sosaya (2010) finished 1–0, a win for Lo Alexander Bravo Jaramillo.
What opening was played in Lo Alexander Bravo Jaramillo vs Eric Mendoza Sosaya?
The game opened with the Ruy Lopez: Exchange Variation (ECO C68).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Lo Alexander Bravo Jaramillo vs Eric Mendoza Sosaya, or open it on the CipherChess analysis board to review it with the Stockfish engine.