Mikhail Braude vs William Paschall
Philadelphia, 1992 · Result 1–0 · East Indian Defense (A48).
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Game details
- White
- Mikhail Braude (2480)
- Black
- William Paschall (2330)
- Result
- 1–0
- Event
- Philadelphia
- Year
- 1992
- Opening
- East Indian Defense (A48)
About this chess game
This chess game between Mikhail Braude (2480) and William Paschall (2330) was played at Philadelphia in 1992 and finished 1–0. The opening was the East Indian Defense (A48). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Mikhail Braude games or William Paschall games? This Mikhail Braude vs William Paschall encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the East Indian Defense.
Frequently asked questions
Who won Mikhail Braude vs William Paschall?
Mikhail Braude vs William Paschall (1992) finished 1–0, a win for Mikhail Braude.
What opening was played in Mikhail Braude vs William Paschall?
The game opened with the East Indian Defense (ECO A48).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Mikhail Braude vs William Paschall, or open it on the CipherChess analysis board to review it with the Stockfish engine.