Bernard Boyle vs Gabor Horvath
Irish International Open, 2019 · Result 0–1 · Queen's Pawn Game: Zukertort Variation (D02).
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Game details
- White
- Bernard Boyle (1799)
- Black
- Gabor Horvath (2128)
- Result
- 0–1
- Event
- Irish International Open
- Year
- 2019
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Bernard Boyle (1799) and Gabor Horvath (2128) was played at Irish International Open in 2019 and finished 0–1. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Bernard Boyle games or Gabor Horvath games? This Bernard Boyle vs Gabor Horvath encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Bernard Boyle vs Gabor Horvath?
Bernard Boyle vs Gabor Horvath (2019) finished 0–1, a win for Gabor Horvath.
What opening was played in Bernard Boyle vs Gabor Horvath?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Bernard Boyle vs Gabor Horvath, or open it on the CipherChess analysis board to review it with the Stockfish engine.