Constantin Botez vs Serban Teodorescu
ROM Ch, 1968 · Result ½–½ · Zukertort Opening (A05).
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Game details
- White
- Constantin Botez (2370)
- Black
- Serban Teodorescu
- Result
- ½–½
- Event
- ROM Ch
- Year
- 1968
- Opening
- Zukertort Opening (A05)
About this chess game
This chess game between Constantin Botez (2370) and Serban Teodorescu was played at ROM Ch in 1968 and finished ½–½. The opening was the Zukertort Opening (A05). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Constantin Botez games or Serban Teodorescu games? This Constantin Botez vs Serban Teodorescu encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Zukertort Opening.
Frequently asked questions
Who won Constantin Botez vs Serban Teodorescu?
Constantin Botez vs Serban Teodorescu (1968) finished ½–½, and the game was drawn.
What opening was played in Constantin Botez vs Serban Teodorescu?
The game opened with the Zukertort Opening (ECO A05).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Constantin Botez vs Serban Teodorescu, or open it on the CipherChess analysis board to review it with the Stockfish engine.