Marcell Borhy vs Andrej Kovac
SVK 1.liga Zapad 2021/2022, 2022 · Result 1–0 · English Opening: Symmetrical Variation, Mecking Variation (A39).
Turn this game into your next win
Replay Marcell Borhy vs Andrej Kovac with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Marcell Borhy (2396)
- Black
- Andrej Kovac (2225)
- Result
- 1–0
- Event
- SVK 1.liga Zapad 2021/2022
- Year
- 2022
- Opening
- English Opening: Symmetrical Variation, Mecking Variation (A39)
About this chess game
This chess game between Marcell Borhy (2396) and Andrej Kovac (2225) was played at SVK 1.liga Zapad 2021/2022 in 2022 and finished 1–0. The opening was the English Opening: Symmetrical Variation, Mecking Variation (A39). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Marcell Borhy games or Andrej Kovac games? This Marcell Borhy vs Andrej Kovac encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation, Mecking Variation.
Frequently asked questions
Who won Marcell Borhy vs Andrej Kovac?
Marcell Borhy vs Andrej Kovac (2022) finished 1–0, a win for Marcell Borhy.
What opening was played in Marcell Borhy vs Andrej Kovac?
The game opened with the English Opening: Symmetrical Variation, Mecking Variation (ECO A39).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Marcell Borhy vs Andrej Kovac, or open it on the CipherChess analysis board to review it with the Stockfish engine.