Albert Bokros vs Sebastian Lukas Kostolansky
ECo-C TCh-SVK 2022-23, 2022 · Result 1–0 · Sicilian Defense: Old Sicilian (B30).
Turn this game into your next win
Replay Albert Bokros vs Sebastian Lukas Kostolansky with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Albert Bokros (2439)
- Black
- Sebastian Lukas Kostolansky (2401)
- Result
- 1–0
- Event
- ECo-C TCh-SVK 2022-23
- Year
- 2022
- Opening
- Sicilian Defense: Old Sicilian (B30)
About this chess game
This chess game between Albert Bokros (2439) and Sebastian Lukas Kostolansky (2401) was played at ECo-C TCh-SVK 2022-23 in 2022 and finished 1–0. The opening was the Sicilian Defense: Old Sicilian (B30). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Albert Bokros games or Sebastian Lukas Kostolansky games? This Albert Bokros vs Sebastian Lukas Kostolansky encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Old Sicilian.
Frequently asked questions
Who won Albert Bokros vs Sebastian Lukas Kostolansky?
Albert Bokros vs Sebastian Lukas Kostolansky (2022) finished 1–0, a win for Albert Bokros.
What opening was played in Albert Bokros vs Sebastian Lukas Kostolansky?
The game opened with the Sicilian Defense: Old Sicilian (ECO B30).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Albert Bokros vs Sebastian Lukas Kostolansky, or open it on the CipherChess analysis board to review it with the Stockfish engine.