Ekaterina Bogdan vs Jayden Z Lee
11. Philadelphia Open, 2017 · Result 1–0 · King's Indian Defense: Sämisch Variation, Normal Defense (E81).
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Game details
- White
- Ekaterina Bogdan (2058)
- Black
- Jayden Z Lee (1682)
- Result
- 1–0
- Event
- 11. Philadelphia Open
- Year
- 2017
- Opening
- King's Indian Defense: Sämisch Variation, Normal Defense (E81)
About this chess game
This chess game between Ekaterina Bogdan (2058) and Jayden Z Lee (1682) was played at 11. Philadelphia Open in 2017 and finished 1–0. The opening was the King's Indian Defense: Sämisch Variation, Normal Defense (E81). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Ekaterina Bogdan games or Jayden Z Lee games? This Ekaterina Bogdan vs Jayden Z Lee encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the King's Indian Defense: Sämisch Variation, Normal Defense.
Frequently asked questions
Who won Ekaterina Bogdan vs Jayden Z Lee?
Ekaterina Bogdan vs Jayden Z Lee (2017) finished 1–0, a win for Ekaterina Bogdan.
What opening was played in Ekaterina Bogdan vs Jayden Z Lee?
The game opened with the King's Indian Defense: Sämisch Variation, Normal Defense (ECO E81).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Ekaterina Bogdan vs Jayden Z Lee, or open it on the CipherChess analysis board to review it with the Stockfish engine.