Juergen Boehm vs Maximilian Reuter
VMCG Open A 2017, 2017 · Result ½–½ · Old Indian Defense: Normal Variation (A55).
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Game details
- White
- Juergen Boehm (2217)
- Black
- Maximilian Reuter (1843)
- Result
- ½–½
- Event
- VMCG Open A 2017
- Year
- 2017
- Opening
- Old Indian Defense: Normal Variation (A55)
About this chess game
This chess game between Juergen Boehm (2217) and Maximilian Reuter (1843) was played at VMCG Open A 2017 in 2017 and finished ½–½. The opening was the Old Indian Defense: Normal Variation (A55). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Juergen Boehm games or Maximilian Reuter games? This Juergen Boehm vs Maximilian Reuter encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Old Indian Defense: Normal Variation.
Frequently asked questions
Who won Juergen Boehm vs Maximilian Reuter?
Juergen Boehm vs Maximilian Reuter (2017) finished ½–½, and the game was drawn.
What opening was played in Juergen Boehm vs Maximilian Reuter?
The game opened with the Old Indian Defense: Normal Variation (ECO A55).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Juergen Boehm vs Maximilian Reuter, or open it on the CipherChess analysis board to review it with the Stockfish engine.