Aaron I Blau vs Jaap Van der Kooij
Corr EU, 1985 · Result 0–1 · English Opening: Anglo-Indian Defense, Queen's Indian Formation (A17).
Turn this game into your next win
Replay Aaron I Blau vs Jaap Van der Kooij with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Aaron I Blau
- Black
- Jaap Van der Kooij
- Result
- 0–1
- Event
- Corr EU
- Year
- 1985
- Opening
- English Opening: Anglo-Indian Defense, Queen's Indian Formation (A17)
About this chess game
This chess game between Aaron I Blau and Jaap Van der Kooij was played at Corr EU in 1985 and finished 0–1. The opening was the English Opening: Anglo-Indian Defense, Queen's Indian Formation (A17). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Aaron I Blau games or Jaap Van der Kooij games? This Aaron I Blau vs Jaap Van der Kooij encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Anglo-Indian Defense, Queen's Indian Formation.
Frequently asked questions
Who won Aaron I Blau vs Jaap Van der Kooij?
Aaron I Blau vs Jaap Van der Kooij (1985) finished 0–1, a win for Jaap Van der Kooij.
What opening was played in Aaron I Blau vs Jaap Van der Kooij?
The game opened with the English Opening: Anglo-Indian Defense, Queen's Indian Formation (ECO A17).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Aaron I Blau vs Jaap Van der Kooij, or open it on the CipherChess analysis board to review it with the Stockfish engine.